Every challenge screen's handle, told apart by id (switch (screen.id)) or narrowed with XxxScreen.is(screen). The union reads the challenge screen declaration, so it cannot name a screen the set does not have.
id
switch (screen.id)
XxxScreen.is(screen)
Every challenge screen's handle, told apart by
id(switch (screen.id)) or narrowed withXxxScreen.is(screen). The union reads the challenge screen declaration, so it cannot name a screen the set does not have.